# Line slope calculator 4x+5y=36

**Straight line given by points A[4; 4] and B[9; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.8x+7.2

**Canonical form of the line equation:**4x+5y-36 = 0

**Parametric form of the line equation:**

x = 5t+4

y = -4t+4 ; t ∈ R

**Slope:**m = -0.8

**Slope angle of line: φ =**-38°39'35″ = -0.6747 rad

**X intercept:**x

_{0}= 9

**Y intercept:**y

_{0}= q = 7.2

**Distance line from the origin:**d

_{0}= 5.6223

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(5; -4)

**Normal vector: n =**(4; 5)

**Midpoint of the segment AB: M =**[6.5; 2]

**Perpendicular Bisector equation:**5x-4y-24.5 = 0

**Vector OA = (4; 4) ; |OA| = 5.6569**

**Vector OB = (9; 0) ; |OB| = 9**

**Scalar product OA .OB = 36**

**Angle ∠ AOB = 45° = 0.7854 rad**